FOR YOU
Q. If x+y+z=0, show that x³+y³+z³=3xyz. Sol: Given, =>x+ y+ z=0 =>x+ y = - z_______(1) =>(x+y)³=( - z)³ =>x³+y³ - 3xy(x+y)= - z³ =>x3+y³ - 3xy( - z)= - z³ [from eqn (1)] =>x³+y³ - 3xyz= - z³ =>x³+y³+z³=3xyz